Data Available: |
Thermal Conductivity |
Thermal Conductivity RRR = 50 |
Thermal Conductivity RRR = 100 |
Thermal Conductivity RRR = 150 |
Thermal Conductivity RRR = 300 |
Thermal Conductivity RRR = 500 |
|
| UNITS | W/(m-K) | W/(m-K) | W/(m-K) | W/(m-K) | W/(m-K) |
| a | 1.8743 | 2.2154 | 2.3797 | 1.357 | 2.8075 |
| b | -0.41538 | -0.47461 | -0.4918 | 0.3981 | -0.54074 |
| c | -0.6018 | -0.88068 | -0.98615 | 2.669 | -1.2777 |
| d | 0.13294 | 0.13871 | 0.13942 | -0.1346 | 0.15362 |
| e | 0.26426 | 0.29505 | 0.30475 | -0.6683 | 0.36444 |
| f | -0.0219 | -0.02043 | -0.019713 | 0.01342 | -0.02105 |
| g | -0.051276 | -0.04831 | -0.046897 | 0.05773 | -0.051727 |
| h | 0.0014871 | 0.001281 | 0.0011969 | 0.0002147 | 0.0012226 |
| i | 0.003723 | 0.003207 | 0.0029988 | 0 | 0.0030964 |
low range |
4K | 4K | 4K | 4K | 4K |
high range |
300K | 300K | 300K | 300K | 300K |
curve fit % error relative to data |
| For Thermal Conductivity only: Curve fit equation of the form: log10 k = (a + cT 0.5 + eT + gT 1.5 + iT 2)/(1 + bT 0.5 + dT + f T 1.5 + hT 2) solves as: k = 10 ( a + cT 0.5 + eT + g T 1.5 + iT 2 ) / ( 1+ bT 0.5 + d T + f T 1.5 + hT 2 ) |
Specific Heat |
Expansion Coefficient |
|
| UNITS | J/(kg-K) | 10-6 * (1/K) |
| a | -1.91844 | -6.06339E1 |
| b | -0.15973 | 2.76779E2 |
| c | 8.61013 | -5.46197E2 |
| d | -18.996 | 5.80100E2 |
| e | 21.9661 | -3.55820E2 |
| f | -12.7328 | 1.26778E2 |
| g | 3.54322 | -2.44575E1 |
| h | -0.3797 | 1.98124E0 |
| i | 0 | 0 |
data range |
4-300 | 4-300 |
equation range |
4-300 | 4-300 |
curve fit % error relative to data |
| For properties: specific heat and expansion coefficient curve fit equation of the form: Curve fit equation of the form: log10 y = a+b(log10T) + c(log10T) 2 + d(log10T) 3 + e(log10T) 4 + f(log10T) 5 + g(log10T) 6 + h(log10T) 7 + i(log10T) 8 Solves as: y = 10 a+b(log10T) + c(log10T) 2 + d(log10T) 3 + e(log10T) 4 + f(log10T) 5 + g(log10T) 6 + h(log10T) 7 + i(log10T) 8 Where: Coefficients a - i are summarized in the appropriate table and T is the temperature in K (x-axis), and y is the property to solve for. |